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12x^2-x-12=-6
We move all terms to the left:
12x^2-x-12-(-6)=0
We add all the numbers together, and all the variables
12x^2-1x-6=0
a = 12; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·12·(-6)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-17}{2*12}=\frac{-16}{24} =-2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+17}{2*12}=\frac{18}{24} =3/4 $
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